630N - Forecast - CodeForces Solution


math *1300

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Python Code:

def bin_pow(a, x):
    if a == 1 or x == 0:
        return 1
    if x == 1:
        return a
    if x & 1:
        return bin_pow(a, x - 1) * a
    else:
        temp = bin_pow(a, x >> 1)
        return temp * temp


def fact(n):
    i = 1
    while n:
        i *= n
        n -= 1
    return i


a, b, c = map(int, input().split())
d = (b * b - 4 * a * c) ** 0.5
print(max((-b + d) / 2 / a, (-b - d) / 2 / a))
print(min((-b + d) / 2 / a, (-b - d) / 2 / a))

C++ Code:

#include<bits/stdc++.h>
using namespace std;
int main()
{
       double a,b,c;
        cin>>a>>b>>c;
        double d=sqrt((b*b)-(4*a*c));
       double x1=(-b+d)/(2*a);
              double x2=(-b-d)/(2*a);
              double mx1=max(x1,x2);
               double min1=min(x1,x2);
              
              
            printf("%.16lf\n",mx1);
               printf("%.16lf\n",min1);
        

   
}


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